Electric water heating question

[flytact]

Since I managed to avoid thermodynamics while getting my engineering degree, I remain baffled by these calculations. Could I get a little guidance or maybe a pat on the back if I'm correct?

If I were to heat 26L of water from 13C to 74C I would do the following:
Heat = Mass x (F-S)
Heat = 26000 (grams) x (74 - 13)
Heat = 1586 kcal

1Kcal = 1.163 watt-hours
1586 = 1364 watt-hours

1.364KW to heat 26L of water from 13C to 71C
So, if I have 2 1000w electric units in a HLT I can expect the water to heat in about 40 minutes (1364/2000*60).

Does this make sense?

[vacant]

Yes, but I'm wondering what are you going to do with the info? Ambient temp, heat loss through boiler, lid on/off and airflow/breeze etc will alter your figure. If you're planning to build a boiler, stick two kettle elements in anyway in case one fails.

[harvs]

Hi

You could use this calculator which says 53 minutes for your scenario. I guess the calculator may include some allowance for inefficiencies

[flytact]

Thanks for the link. I searched and searched the forums, just not the site itself

I'm building an HLT from a sanke keg and don't want to deal with propane at the height the HLT will be located. The kettle will have a lid and possibly insulation in the future.